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lrint函数
lrint() function is a library function of cmath header, it is used to round the given value and convert it to a long integer. It accepts a value (float, double, or long double) and returns a long integer value after rounding it based on the rounding direction specified by fegetround() function.
lrint()函数是cmath标头的库函数,用于舍入给定值并将其转换为长整数。 它接受一个值( float , double或long double ),并在根据fegetround()函数指定的舍入方向将其舍入后返回一个长整数值。
Syntax of lrint() function:
lrint()函数的语法:
C++11:
C ++ 11:
long int lrint (double x); long int lrint (float x); long int lrint (long double x); long int lrint (T x);
Parameter(s):
参数:
x – represents the value to round.
x –表示要取整的值。
Return value:
返回值:
The returns type of this function is long int, it returns a long integer value rounded to nearby integral.
此函数的返回类型为long int ,它返回一个四舍五入到附近整数的长整数值。
Example:
例:
Input: float x = 123.4f; Function call: lrint(x); Output: 123 Input: float x = 123.5f; Function call: lrint(x); Output: 124
// C++ code to demonstrate the example of// lrint() function#include#include #include // for fegetround()using namespace std;int main(){ float x = 0.0f; cout << "Specified rounding is: "; switch (fegetround()) { case FE_DOWNWARD: cout << "Downward" << endl; break; case FE_TONEAREST: cout << "To-nearest" << endl; break; case FE_TOWARDZERO: cout << "Toward-zero" << endl; break; case FE_UPWARD: cout << "Upward" << endl; break; default: cout << "Unknown" << endl; } x = 123.4f; cout << "lrint(" << x << "): " << lrint(x) << endl; x = 123.5f; cout << "lrint(" << x << "): " << lrint(x) << endl; x = 123.6f; cout << "lrint(" << x << "): " << lrint(x) << endl; x = -123.4f; cout << "lrint(" << x << "): " << lrint(x) << endl; x = -123.5f; cout << "lrint(" << x << "): " << lrint(x) << endl; x = -123.6f; cout << "lrint(" << x << "): " << lrint(x) << endl; return 0;}
Output
输出量
Specified rounding is: To-nearestlrint(123.4): 123lrint(123.5): 124lrint(123.6): 124lrint(-123.4): -123lrint(-123.5): -124lrint(-123.6): -124
Reference:
参考:
翻译自:
lrint函数
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